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Two reverse-horizontal curves have external angles Δ1 = 30° and Δ2 = 60°. The distance between

PI and PI is 1000 ft. The maximum allowable side friction factor is 0.06, and the maximum

super-elevation rate is 0.06. What is most nearly the maximum velocity (design speed) that can be

provided while allowing for a 3 sec tangent distance between curves? 42 mph

I have not been able to come up with the correct solution to this problem. Can someone please post their solution so that I can figure out my mistake. Any additional explanation on the solution would be helpful.

Thanks

owillis

 
Count me in too! I also do better with structure.
Does anyone know if the Construction module is new to the breadth portion in the 2008 exam spec? I know that it is a new depth module.

I'll be doing WR depth.
Yeah, its a new breadth module as well though somethings have been moved around from other sections, to make it a complete section.

 
Hey I am interested too, Im taking the construction come April, also have lots of study material...mostly in .pdf form. Have material for all depths though.
Can folks post all the material they have so that we could use them? Thanks - would be very helpful.

 
Two reverse-horizontal curves have external angles Δ1 = 30° and Δ2 = 60°. The distance betweenPI and PI is 1000 ft. The maximum allowable side friction factor is 0.06, and the maximum

super-elevation rate is 0.06. What is most nearly the maximum velocity (design speed) that can be

provided while allowing for a 3 sec tangent distance between curves? 42 mph

I have not been able to come up with the correct solution to this problem. Can someone please post their solution so that I can figure out my mistake. Any additional explanation on the solution would be helpful.

Thanks

owillis
Supplied solution:

The minimum radius and the velocity are related by

R= v2/15( e+f ) = v2/( 15 )( 0.06+0.06 ) = v2/1.8

The tangent legs of the curves are given by

T1 =Rtan Δ 1^ 2 =( v 2 1.8 )tan 30°^2 =.149 v^2 T 2 =Rtan Δ2^2 =( v^2*1.8 )tan 60°^2 =0.32 v^2

The tangent distance for a 3 sec transition between curves can be calculated from

t=1.47 t t v=( 1.47 )( 3 sec )v=4.41v

The total available distance is 1000 ft.

1000 ft=t+ T1 + T2 1000 ft=4.41 v+.149 v 2 +0.32 v 2 v 2 +9.39 v−2129=0

v= (−B± B2 −4AC)/2A = − 9.39 ± ( 9.39 ) 2 −( 4 )( 1 )( −2129 ) ( 2 )( 1 ) =41.7 mi / hr ( 42 mph

)

Sorry, a lot of the text formatting got lost, so it's hard to decipher. I tried to add in some of it...

 
Yay construction questions!!!
A contract has 90 days remaining until completion. Advance completion will be paid $10,000 bonus per

day. The most critical activity duration can be shortened by employing more crews. There is a

reduction in efficiency as the number of crews increase; that is, the number of schedule days saved is

not directly proportional to the number of crews added. For each crew added, the cost is $2800 per

day for labor and equipment. If crews must be added as a complete unit, how many crews can be

added without exceeding the bonus amount? 1

crews added added crew cost per day schedule days reduced

1 $2800 20

2 $5600 26

3 $8400 30

Excavation quantities have been determined from cross sections and must be adjusted for shrinkage.

Tabulated here are the unadjusted volumes required. Shrinkage is 10%. The cut volume increases

18% when hauled in 15 yd3 capacity trucks. How many truckloads of borrow are required? 44

station cut fill

(yd3) (yd3)

20 1500 0

21 1350 0

22 800 500

23 250 950

24 0 1200

25 0 1400

A compacted fill is to be constructed with a total volume of 10 000 m . The fill is to be compacted to a

dry unit weight of at least 20 kN/m and a minimum water content of 10%. Soil in the borrow area has

a dry density of 19.0 kN/m and an average water content of 8%.

The weight of soil solids required to build the fill is most nearly 200,000Kn

A compacted fill is to be constructed with a total volume of 10 000 m . The fill is to be compacted to a

dry unit weight of at least 20 kN/m and a minimum water content of 10%. Soil in the borrow area has

a dry density of 19.0 kN/m and an average water content of 8%.

The amount of borrowed material that must be removed is most nearly 11,000 m3

Asphalt paving operations have been described as a system of four items: batch plant operation,

transporting, placing, and rolling. A contractor has a project that requires critical airport paving in a

strict 40 hr time window. Using equipment matched to the asphalt paver production rate, the

contractor's historical reliability of the equipment is shown in the table.

Due to the critical nature of the project, the contractor has decided to assign a second paver to the

job, while using the same amount of other equipment that would support a single paver. What is the

reliability of the paving system for this project? 0.93

equipment reliability

a batch plant 0.97

b hauling equipment 0.99

c asphalt paver 0.90

d rolling equipment 0.98

An asphalt paving surfacing alternative is being evaluated using the present worth for future

expenditures over an expected 40 yr life. The initial cost of the asphalt surface is $700,000. It will

require overlays at several intervals during the expected life. The cost of the future overlays will be

$252,000 at 10 yr from construction, $332,000 at 17 yr, $420,000 at 23 yr, $530,000 at 29 yr, and

$671,000 in 35 yr. The inflation rate is set at 4% annually for the analysis. What is the present worth

of the asphalt alternative? $1,550,000

Do you have the worked out solutions to these?

 
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