J-Dubbs
Doesn't get thermodynamics
I think my point has gotten lost b/c I did not do a good job explaining.
Let say 5 questions (out of 80) are thrown out before scoring the exam and an arbitrary (I am making this up) score of 53 correct (after problems removed) is chosen as the passing # for this exam.
If you had 54 questions correct (before the 5 problems were removed) but 2 of the 54 originally correct were thrown out, your correct score # is 52 = fail.
If you had 54 questions correct (before the 5 problems were removed) and 0 of the 54 originally correct were thrown out, your correct score # is 54 = pass.
That's what I meant by "if thrown out, hurts your chances of passing."
Bottom line as previously said, get as many correct as possible!
I'm wary to join in here, but I just want to say that this would make no sense for them to grade this way. Not only is it unfair, but it would skew scores in a way that isn't representative of the sample of test-takers. Doing it this way would actively penalize those who got more difficult questions correct. That makes zero sense.
More likely it would be one of two options:
- The number of questions you answered correctly remains the same, but they reduce the overall number of questions by how many they decided weren't appropriate. So if you originally got 55/80 correct and they threw out 3 questions, you now have a score of 55/77. So your score goes from 69% to 71%.
- They simply give credit to everyone for the questions that were deemed inappropriate for the exam. So if you originally got 55/80, and the 3 questions they threw out were ones you missed, your score is raised to 58/80. So your score goes from 69% to 73%.
It's all conjecture of course. You could certainly be right, and there are probably many other ways of curving it that we haven't thought of. But if they're fair about it, I don't see them doing it the way you mentioned.