Problem 530 (NCEES)

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MVA Method

40MVA in series with 25 MVA (1MVA/.04)

40 X 25 / (40+25) = 15.38 MVA

Fault is on the 480v bus

15.38MVA/(sqrt(3) * 480e-6MV) = 18,500A
Wow, thank you so much! This was definitely easy to solve. 

 
what is 12.47-kv-480Y/277-V mean?

Does it mean that the primary is in the range 12.47-480 kv, Y connection? And the secondary is 277-V?
 
It means Primary is 12.47kV ( Delta) and secondary is 480V (Y connection) 480V Line voltage and 277 is Line to Neutral Voltage.
 
what is 12.47-kv-480Y/277-V mean?

Does it mean that the primary is in the range 12.47-480 kv, Y connection? And the secondary is 277-V?
12.47 kV is the distribution line voltage (High side voltage). It could be 3 wire Delta 12.47 kV (no ground wire connection) or 4 wire WYE 7.2 kV (12.47/sqrt(3)=7.2) line-ground, 12.47 kV line-line). It depends on how you connect the transformer.

The low side winding of each single phase transformer is 277V line to ground. WYE configuration is three phases line to ground. If you measure between two phases 277V@ 0 deg and 277V @120 deg, you will read 480 V line to line. Or 277*sqrt(3) = 480V.

So each single phase transformer could be: 12.47kV/277V (Delta HS/ WYE LS) or 7.2kV/277V (WYE HS/WYE LS).
There is no 480V winding, it is a product of the phase angles.

Note, it could be a 3 phase transformer, which includes all three single phase sets of windings inside one transformer. In practice an overhead transformer bank (on the pole) is usually 3 individual transformers. And underground pad mount (on the ground) transformers are generally 3 phase transformers.
 
Last edited:
we can use MVA Method, 40MVA in series with 25 MVA (1MVA/.04)
and 40 X 25 / (40+25) = 15.38 MVA
we find out that Fault is on the 480v bus
15.38MVA/(sqrt(3) * 480e-6MV) = 18,500A
 
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