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Three guests check into a hotel room. The manager says the bill is $30, so each guest pays $10. Later the manager realizes the bill should only have been $25. To rectify this, he gives the bellhop $5 as five one-dollar bills to return to the guests.

On the way to the guests' room to refund the money, the bellhop realizes that he cannot equally divide the five one-dollar bills among the three guests. As the guests are not aware of the total of the revised bill, the bellhop decides to just give each guest $1 back and keep $2 as a tip for himself, and proceeds to do so.

As each guest got $1 back, each guest only paid $9, bringing the total paid to $27. The bellhop kept $2, which when added to the $27, comes to $29. So if the guests originally handed over $30, what happened to the remaining $1?
I hate these types of riddles. They confuse you with the second half and then make you forget about the manager and his register.

$30 = $1 in guest pockets *3 = $3 + $2 in sneaky lying bellhop pocket = $5 + $25 in the register = $30
 
I hate these types of riddles. They confuse you with the second half and then make you forget about the manager and his register.

$30 = $1 in guest pockets *3 = $3 + $2 in sneaky lying bellhop pocket = $5 + $25 in the register = $30
Yup. Why add bellhop stolen money to what the guests paid.

Guests paid 27 and manager + bellhop received 25 + 2.
 

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