STEEL MAN
Man of Steel
roe=(.85k1f'c)/(fy)[87/(87+fy)]k1=.85-.05(fc-4) -------when f'c>4ksi
.75Asb=.75(roe)B(d)
a=(.75(Asb)fy)/((.85F'c)xB)
Mu=theta(.75Asb)fy[d-a/2]------------------Maximum moment with no compression steel.
As=Mu/(4d)
Mu in kip-ft
d=effective depth in inches
round to actual steel sizes.
Solve for thetaMn.
or
Solve for a in terms of As then quadratic for As. Check moment for tension controlled.
Steelman, the more you make me think about it, the harder it does seem to do in 6 min. But i dont think its a 15 min problem. Maybe 8 or 10 i dont know.......
Blair,
good approach too, I appreciate your input on this makes me think another approach, yes I agree it is tough to sovle these problems in maximum time of 6mins, I always tried solving all the problems I can in 6mins maximum.
good luck to you on the PE exams and everyone who contributed to this topic.