BebeshKing PE
THIS IS THE WAY
No, it only appears that way because with the smaller wires, the resistance has more of an impact. As the wire size gets larger, the effective Z becomes closer to XL.
So if the given is the circuit power factor, we need to use the approximate formula(per NEC)?It's because the angle of the load cannot be directly translated to the angle of the "circuit." The phase angle of the circuit is different from the power factor of the load. The impedance of the conductors will change the power factor of the current supplying the load.
And if the given is the load power factor, we need to use the complex number formula ?
If I understand this problem correctly, the 0.75 pf is the load power factor and we need to use the complex number formula and the answer would be 1.13V?