kduff70
Well-known member
Can any help me lock down the concept of Vbase through a transformer ? I have attach a problem from Kaplan PE Power exam. I'm stuck on how they solve for the base voltage on the motor side of the problem.
The have the solution saying Vbase = 22 (220/25) (13/sqrt3*130) give you 11.1775 as the Vbase , Can some show how to go about this .
View attachment Impedancetransf.pdf
The have the solution saying Vbase = 22 (220/25) (13/sqrt3*130) give you 11.1775 as the Vbase , Can some show how to go about this .
View attachment Impedancetransf.pdf
