passpepasspe
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I am getting stuck on the example 2.5 (age 19) of the reza mallhati book.
I understand up until the equation of original ground from P to CP = y = mx +b.
I don't understand how one arises to the equation Yp = 868 + .1(3) = 868.3 feet. I don't understand where does the 3 come from. and how do the following equations come about.
Do you guys think the example 2.5 of is of equal difficulty of exam level? It seems complex to me.
I understand up until the equation of original ground from P to CP = y = mx +b.
I don't understand how one arises to the equation Yp = 868 + .1(3) = 868.3 feet. I don't understand where does the 3 come from. and how do the following equations come about.
Do you guys think the example 2.5 of is of equal difficulty of exam level? It seems complex to me.