NCEES 515 new exam format

[cabby]

Has anyone worked this problem yet? I am not sure how they are getting 2 times the peak voltage? Does the capacitor charge to the same voltage as the 120Vrms source? Then do KVL which would give you 240Vrms. Or sqrt2 * 240Vrms=339Vpeak? I am not sure if this is the right approach or not.

thanks,

cabby

 

[Flyer_PE]

The capacitor charges to approximately the positive peak voltage of 120*sqrt2 = 169.7 V

When the voltage wave reaches the negative peak, the reverse voltage across the diode will be twice this value.