P pkarna77 Member Joined Dec 15, 2012 Messages 15 Reaction score 1 Dec 7, 2017 #1 David's book is the best for SE preparation for bridge section. David, could you please shed light on Problem#17(Page-61): how you have calculated Avf=4*0.2=0.8 in^2/ft?
David's book is the best for SE preparation for bridge section. David, could you please shed light on Problem#17(Page-61): how you have calculated Avf=4*0.2=0.8 in^2/ft?
L leggo PE Straight Waffle-izer Joined Dec 9, 2016 Messages 17,946 Reaction score 3,400 Location California Dec 7, 2017 #2 @David Connor, SE, could you help @pkarna77 out here?
David Connor SE Well-known member Joined Dec 3, 2015 Messages 248 Reaction score 92 Dec 7, 2017 #3 The interface bars are (2)-#4 bars spaced at 6" o.c. The area of reinforcement per linear ft is (4) bars per ft. with 0.2 sq. inches per bar. Therefore, Avf = 0.8 sq in.
The interface bars are (2)-#4 bars spaced at 6" o.c. The area of reinforcement per linear ft is (4) bars per ft. with 0.2 sq. inches per bar. Therefore, Avf = 0.8 sq in.