A simple single phase power line with a motor question

[sbsklewis]

For some reason I am not getting the answer.

A single phase power line with a purely resistive impedance of 200 ohms per conductor delivers power to an induction motor that requires 800 watts input power. Determine the generator power delivered to the line and motor combination, assuming a line current of 5 amperes.

I get 5800 watts, but the answer is 10800 watts.

 

[PE blues]

Your line losses will be i(square)*R*2 for 1phase line

 

[sbsklewis]

You are right, I have got to keep that straight. Thanks

 

[Redskinsdb21]

I get I^2*(200*2) = 10,000...why do you add the 800?

 

[Flyer_PE]

^The motor gets the other 800.

 

[nasir]

Why are you multiplying 2? I never seen that...I though the line loses are: I^2*R, but don't get the other 2.

 

[Flyer_PE]

^Since it's a single phase load, current will be flowing in both conductors.

 

[jcbabb]

For some reason I am not getting the answer.

A single phase power line with a purely resistive impedance of 200 ohms per conductor delivers power to an induction motor that requires 800 watts input power. Determine the generator power delivered to the line and motor combination, assuming a line current of 5 amperes.

I get 5800 watts, but the answer is 10800 watts.

NASIR,

Each conductor (both coming and going) has the 200 ohm impedance. Effectively the power dissipated is:

P= (5^2)200 + 800W + (5^2)200

or

P = (5^2)(200*2) + 800W