I think I got it now.
NCEES 125)
Since transformer 1 has the least capacity (1000kVA) and we don't want to overload it, then Sa=(MVAa/puZa)*Stotal/(MVAa/puZa+MVAb/puZb) So 1000=(1000/4.5)*Stotal/(1000/4.5+2000/6) Solve this for Stotal; it gives Stotal =2500kVA
The maximum total load (KVA) is 2500KVA. The NCEES answer is correct.
Just to confirm: Yes very right
Transformer 1 will contribute 1000 KVA of the 2500 KVA total load. so 2500-1000=1500
For transformer 2:
Sb=(MVAb/puZa)*Stotal/(MVAa/puZa+MVAb/puZb) So Sb=(2000/6)*Stotal/(1000/4.5+2000/6) Solve this for Sb; it gives Sb =1500kVA This is right but if you take 2000 kva supplied by T2; the Stotal will be different at 3333.33KVA implying overloading of T1.
Transformer 2 will contribute 1500 KVA of the 2500 KVA total load. yes
And it makes sense that Sa + Sb = 1000 KVA + 1500 KVA = 2500 KVA total load. yes
Thanks!
It is my pleasure but still if I were you I will strength my pu chapter.