DanHalen
Well-known member
The problem states:
A hydraulic jump occurs in a trapezoidal channel with a 4.2 m bottom width and 1:1 side slopes. The flow in the channel is 38 m3/sec and the water depth upstream of the jump is 0.74 m. What is the water depth downstream of the jump?
(A) 0.69 m
(B) 0.74 m
C) 2.3 m
(D) 3.3 m
The solution is fairly straight forward but I don't get the same answer. I keep getting 0.74 m and the answer should be 3.34 m. I use the Solve function on my calculator and it keeps giving me the same answer. I haven't been able to find an errata for this problem so I want to see if anyone else gets the same answer as me. This is what I'm using in my Casio FX-115:
(3.66*0.74)+((382)/(9.81*3.66))=X2(2.1+0.33X)+((382)/(9.81*(4.2X+X2)))
Hit solve and X = 0.74 m
A hydraulic jump occurs in a trapezoidal channel with a 4.2 m bottom width and 1:1 side slopes. The flow in the channel is 38 m3/sec and the water depth upstream of the jump is 0.74 m. What is the water depth downstream of the jump?
(A) 0.69 m
(B) 0.74 m
C) 2.3 m
(D) 3.3 m
The solution is fairly straight forward but I don't get the same answer. I keep getting 0.74 m and the answer should be 3.34 m. I use the Solve function on my calculator and it keeps giving me the same answer. I haven't been able to find an errata for this problem so I want to see if anyone else gets the same answer as me. This is what I'm using in my Casio FX-115:
(3.66*0.74)+((382)/(9.81*3.66))=X2(2.1+0.33X)+((382)/(9.81*(4.2X+X2)))
Hit solve and X = 0.74 m