kduff70
Well-known member
[SIZE=10.5pt]I was going through Graffeo ex .26 on page 57-58 I don’t quit understand the equation he uses to solve for the fault current why is it 1 over the impedance? And is the 35,555A the current over the eight circuit break. And will it be 4444 A across each of the circuit breaker. I have attached the problem[/SIZE]
SKMBT_42015080407560.pdf
SKMBT_42015080407560.pdf