E
eric08
I think I'm losing my mind! This problem gives the total unit weight as 127 lb/ft3 and the unit weight of the solids as 165.4. Is this possible?
PLEASE help!
PLEASE help!
I think we're making the same point. because their giving me a total unit wieght that is smaller than the unit wieght of the solids (total=127, solids=165.4)Mathematically this means Unit Wt = Mass/Volume, where the volumetric contributions of water and void space (are) are RELATIVELY weighted more which means that the unit weight of solids will typically be LESS THAN the total unit weight.
Total Unit Weight = (Mass of Solids + Water + Void Space)/(Volume of Solids + Water + Void Space)
I think we're making the same point. because their giving me a total unit wieght that is smaller than the unit wieght of the solids (total=127, solids=165.4)
I don't have the problem to look at, but I think you missed jr's point above.
I'm assuming that what you're reporting as "total unit weight" is the in-situ or dry unit weight (127), either way it includes void spaces, whether it be water or air...the matter filling those void spaces has a unit weight less than that of the solids (165.4). So, a cubic foot of the soil weighs less than what a cubic foot of the solids would weigh.
yeah, so the unit weight of the solids is 165.4 #/c.f. and the total unit weight of the soil is 127 #/c.f., as explained above. In one cubic foot of soil, you have less than a cubic foot of solids. If you still don't understand, you'd probably benefit from reading a little from a soil mechanics book. This topic can be confusing.Problem #6 ( 6 min. sol.) Given the phase diagram shown, what is most nearly the porosity?
yeah, so the unit weight of the solids is 165.4 #/c.f. and the total unit weight of the soil is 127 #/c.f., as explained above. In one cubic foot of soil, you have less than a cubic foot of solids. If you still don't understand, you'd probably benefit from reading a little from a soil mechanics book. This topic can be confusing.
What are you going to take in the PM?woohoo! i'm not the only one studying!!!!!
In the solution, it states "By assuming a unit value for the total volume, an equation for the void ratio can be simplified to determine the porosity." How did they do that?????????????????????yeah, so the unit weight of the solids is 165.4 #/c.f. and the total unit weight of the soil is 127 #/c.f., as explained above. In one cubic foot of soil, you have less than a cubic foot of solids. If you still don't understand, you'd probably benefit from reading a little from a soil mechanics book. This topic can be confusing.
I don't know what they mean, but I can show you the steps I would use to solve this problem.In the solution, it states "By assuming a unit value for the total volume, an equation for the void ratio can be simplified to determine the porosity." How did they do that?????????????????????
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