Vertical steel Channel (3 bolts) with 500 lb force on the end. When calculating the secondary shear force , where does NCEES's formula come from ?
F = 9500 (6) / 2 (36). I know the 9500 is the moment , but I'm guessing on the rest: the 2 is the number of bolts ?(the 3rd bolt is actually the centriod of the bolt pattern), the 6 is the distance from the centriod ? , what about the 36 ? 6x6 ?
MERM 51-16 has eccentric loaded arms & critical fasteners , but do not see this equation.
You would think a professional publication would include the equation, units, and NO ERRORS !
Any help would be greatly appreciated.
Thanks
F = 9500 (6) / 2 (36). I know the 9500 is the moment , but I'm guessing on the rest: the 2 is the number of bolts ?(the 3rd bolt is actually the centriod of the bolt pattern), the 6 is the distance from the centriod ? , what about the 36 ? 6x6 ?
MERM 51-16 has eccentric loaded arms & critical fasteners , but do not see this equation.
You would think a professional publication would include the equation, units, and NO ERRORS !
Any help would be greatly appreciated.
Thanks