VoltageDrop
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When they convert the load voltage VAB to Van, what relationship causes it to be shifted by -30 degrees?
This is the alternate way I posted above Vab = VAB + IaA * Z lineWhy do they not use 2 time R+jX because where the terminals Vab are you would have the impedance of b as well. Any help would be appreciated
Thanks
Dean,Soma,
The load is delta connected so when you convert to Y (line to ground) the voltage will lag by 30 deg since the reference voltage is 0 deg. You will see this if you draw the phasor diagram. NCEES method is correct.
Dean
I thought I was going crazy looking at the solution because I thought the same as you.. I think my mind is just burnt out, need to relax before Friday,,,It's a delta connected load, so voltages do not shift nor do they change magnitude. Just use Vab = VAB + IaA * Z line. Though the answer is correct, the method used in the solution is wrong.
totally agree! in this delta connection, its phase voltage is also 12.5kv, so no √3 need to be divided by, mistake! We have to use line-neutral, line-line term.I think we are getting confused with the definition of phase voltage vs line to neutral voltage. I had this discussion with my boss, who used to be a professor, and he railed on me for using the term line voltage and phase voltage as it is too ambiguious as to what the voltage actually is being discussed. I think I like his opinion that phase voltage should never be used as it can be confusing. We should always use either line to line or line to neutral in discussing voltages.
What is everyone's thoughts on this? Soma, I hate to pick on you, but it seems this is where some confusion is?
Hey way to revive a 4+ year old thread!!! :thumbs:totally agree! in this delta connection, its phase voltage is also 12.5kv, so no √3 need to be divided by, mistake! We have to use line-neutral, line-line term.
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