It's easy to calculate mercury emissions using the emission factors published in EPA's
AP-42 on-line document.
Coal combustion is covered under
Chapter 1.1 for bituminous and subbitumunous coal, and
Chapter 1.2 for anthracite coal.
Of course, you reallyneed to know some specifics about the power plant, such as what type of combustion system it uses, and what kind of emissions controls are used.
If your 50 MW power plant is burning bituminous or subbituminous coal (anhtracite is pretty limited in use), the mercury output could be calcualted as follows:
Let's assume "controlled" coal combustion. The emission factor for mercury (Hg) would be:
(Ref. Table 1.1-18, AP-42, Sept. 1998)
Bituminous coal: Hg: 8.3E-05 lb/ton (applies per ton of coal feed, as fired)
Note: this factor applies "to boilers utilizing either venturi scrubbers, spray dryer absorbers, or wet limestone
scrubbers with an electrostatic precipitator (ESP) or Fabric Filter (FF). In addition, the factors apply
to boilers using only an ESP, FF, or venturi scrubber."
(I won't calculate it, but I will post the mean emission factor for anthracite coal, which is significantly higher at 1.3E-04 lb/ton, as per table 1.2-7 , AP-42, Oct. 1996)
Now you just need to figure out how many tons per day need to be burned to generate 50 MW. As per the AP-42 chapter 1.1:
Let's just use the mean of the range for as mined bituminous coal - 12,725 Btu/lb, or 2.55E7 Btu/ton.
Converting to kW-hr: 2.55E7 Btu/ton x 2.928E-04 kW-hr/Btu = 7466.4 kW-hr/ton, or 7.45 MW-hr/ton.
To obtain 50 MW of energy from the coal: 50 MW / (7.45 MW-hr/ton) = 6.7 tons per hour.
This is where you would really need to get some specifics from a real 50MW power plant, because obviously there are inefficiencies, and some greater amount of coal would be required to actually generate 50 MW of electricity. I have no idea what those efficiencies might be.
So, just guessing that the boilers and generators are 80% efficient at converting the heat energy, the total coal feed needed would be:
6.7 tph/0.8 = 8.38 tons per hour. So, multiplying by 8760 hours per year, you get: 73,409 tons of coal burned per year. Going back to our emissions factor, we get:
8.3E-05 lb Hg/ton coal x 73,409 tons coal/year =
6.1 pounds per year of mercury, using bituminous coal fired from a plant with emissions controls.