Absolutely correct!I get C.
Maximum stress = tensile stress + bending stress = F/A + My/I = 3000/(2*t) + 3000lb(3in)/(1/12*t*2^3) = 30000 when t = 0.5.
Yes, that makes sense. I wanted to make sure there isn't some way to know the orientation without the additional view.
This is correct.D.
The bending moment due to P2 causes a normal stress distribution at cross section a-a. At point A the magnitude of normal stress is zero and therefore independent of h.
This is correct.I think you have it backwards. Shear stress due to torsion is zero at the center and increases to a maximum at the external fibers.
Enter your email address to join: