Wow, that is kind of a crappy question. I don't remember anything that tricky on the test.
With that process, you are heating and dehumidifying. It can be done in one process by a dessicant heat wheel, but I've not seen one used for reheat.
Typically, reheat is used to allow the coil to dehumidify the air, and sensible heat is added so as not to change the temperature of the room. Also, it can be used when multiple spaces with different cooling profiles are on one system, for better control.
In this process, you're going from 53F DB / 52F WB / 21.43 (btu/lbm) / 56.2015 grains/lbm
to
60F DB / 51F WB / 20.821 (btu/lbm) / 41.3232 grains/lbm
As you can see, you've raised temperature (53F to 61F), while removing moisture (56.2015 grains to 41.3232 grains).
So, let's use your equation. Qt = mdot * (delta h)
At standard conditions, the specific volume of air is 13.333 ft^3/lbm. So, mdot = [(60 min/hr) / 13.333 ft^3/lbm] * Vf = 4.5 (lbm*min/ ft^3 * hr) * Vf (in CFM)
Therefore, total heat load is approximated as 4.5 * CFM * (delta h). (there's one of those to remember!)
From the above values, 4.5 (lbm*min / ft^3 * hr) * 8000 (ft^3/min) * (21.43 - 20.821) btu/lbm = 21,924 btu/hr
The sensible component is calculated by this equation. Qs = mdot * Cp * (delta T)
We know that mdot = 4.5 (lbm*min/ ft^3 * hr) * Vf (in CFM). For standard conditions, Cp for air is .240 btu/lbm * F.
Combining these, we get 1.08 (btu * min / ft^3 * F * hr) * Vf (ft^3/min) * delta T (F), or 1.08 * CFM * (delta T).
From the above, 1.08 (btu * min / ft^3 * F * hr) * 8000 (ft^3/min) * (60F - 53F) = 60,480 btu/hr
For the latent component, Ql = mdot * specific h * (delta W).
At standard conditions, specific enthalpy for air is assumed at 1075.5 btu/lbm (or so).
So, 4.5 (lbm*min/ ft^3 * hr) * Vf (in CFM) * 1075.5 btu/lbm = 4840 (btu * min / ft^3 * hr) * Vf (ft^3 / min) * delta W (lbmwater/lbmair)
or, 4840 * CFM * (delta W)
4840 (btu * min / ft^3 * hr) * 8000 (ft^3/min) * [( 56.2015 - 41.3232 ) grains/lbma * 1 lbmw/7000 grains] = 82,298 btu/hr
Qt = Qs + Ql
Qt = 21,924 btu/hr
Qs = 60,480 btu/hr
Ql = 82,298 btu/hr
Hmmm.....
Here is where you have to think about the process. You're raising temperature (adding heat) and lowering moisture content (removing heat, or energy, if you see it better that way).
With that, (60,480 btu/hr) + (-82,298 btu/hr) = -21,818 btu/hr, which is approximately what we found for Qt.
If the question didn't ask what was the sensible heat load, then it's just something you have to know. Typically, heating is a sensible process only.
A better question would have been 53/52 heated to 60/55. That is a sensible process only.