joshtrevino
Member
I need help understanding this differential relay problem.
Problem Statement:
A three phase, delta-wye-connected, 30MVA, 33/11kv transformer is protected by a differential relay. Calculate the relay current setting for faults drawing up to 200 percent of the rated current. The CT ratio on the primary side is 500:5, and that on the secondary side is 2000:5.
Problem Solution:
Primary rated current = 30000/(1.73*33) = 524.88 amps; Secondary rated current = 3*(524.88) = 1574.64 amps
CT current on primary = 524.88*(5/500) = 5.249 amps; CT current on secondary = 1574.64*(5/2000)*(1.73) = 6.818 amps
Relay current at 200% of the rated current = 2*(6.818-5.249) = 3.3138 amps
My question: Why is the CT current from the wye connected secondary multiplied by 1.73 (the square root of 3)???
If anything, I would think that we would need to multiply the primary side by square root of 3 because it is a delta connection.
Please help.
Problem Statement:
A three phase, delta-wye-connected, 30MVA, 33/11kv transformer is protected by a differential relay. Calculate the relay current setting for faults drawing up to 200 percent of the rated current. The CT ratio on the primary side is 500:5, and that on the secondary side is 2000:5.
Problem Solution:
Primary rated current = 30000/(1.73*33) = 524.88 amps; Secondary rated current = 3*(524.88) = 1574.64 amps
CT current on primary = 524.88*(5/500) = 5.249 amps; CT current on secondary = 1574.64*(5/2000)*(1.73) = 6.818 amps
Relay current at 200% of the rated current = 2*(6.818-5.249) = 3.3138 amps
My question: Why is the CT current from the wye connected secondary multiplied by 1.73 (the square root of 3)???
If anything, I would think that we would need to multiply the primary side by square root of 3 because it is a delta connection.
Please help.