6 mins enough for PE Civil struc PM per Prob?

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roe=(.85k1f'c)/(fy)[87/(87+fy)]k1=.85-.05(fc-4) -------when f'c>4ksi

.75Asb=.75(roe)B(d)

a=(.75(Asb)fy)/((.85F'c)xB)

Mu=theta(.75Asb)fy[d-a/2]------------------Maximum moment with no compression steel.

As=Mu/(4d)

Mu in kip-ft

d=effective depth in inches

round to actual steel sizes.

Solve for thetaMn.

or

Solve for a in terms of As then quadratic for As. Check moment for tension controlled.

Steelman, the more you make me think about it, the harder it does seem to do in 6 min. But i dont think its a 15 min problem. Maybe 8 or 10 i dont know.......

Blair,

good approach too, I appreciate your input on this makes me think another approach, yes I agree it is tough to sovle these problems in maximum time of 6mins, I always tried solving all the problems I can in 6mins maximum.

good luck to you on the PE exams and everyone who contributed to this topic.

 
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