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Folks, I pass the PE exam on the third trial. Here are my receipes: In April 2011, I took a prep class to prepare me for the exam. It was totally useless so when I sat for the first time, surprisingly I was ready for maybe 40% of the exam. It was a shock to me. In October of the same year, I...

If the phase angle is 45 degree, what would be the frequecy?

Given an angle Teta=45. How you would find its frequency?

It is correct because the rotor field motor is always slightly less than the synchronous motor. Therefore, we p=4, you are able to calculate sync rpm which is sync rpm = 120 * 500 / 4 sync rpm = 15000 rpm. I believe your approach is correct.

I have done it a couple of times. No big deal!! By the way, it is not mandatory.

Bethy, here is my email address [email protected]. Thanks!!

Bethy Can you email me as well the GA fTech older. Thanks in advance!!

All right!! No need to buy the 2011 version. Thanks!!

For PE October exam, will we be using NEC 2008 or NEC 2011?

Thanks for the link. Very useful!!

Thanks everyone for the reply.

a) Calculate the approximate values of full load current, starting current and no load current of a 75KW, 4000, 3-phase, 900 r/min, 60Hz induction motor. B) Calculate the nominal full-load sped knowing that slip is 2 %? My question is what do they mean by Nominal Full-Load-Speed? Thanks!!

CableGuy, do you think the entire section 5 is enough for VFD questions on the exam?. Thanks!!!

Thanks a lot cableguy. Very useful!! I am getting very confident for the April exam. 2 more weeks to go.

Do you guys think that F.E Enginering Economics materials are enough for the P.E exam? Please, advise.

The MVA method seems to be shorter but it feels good to know more than one method. Thanks for your quick response. Great forum!!

I will double check the site. Thanks!!

Thanks sam314159. Neat job!!!

Very Neat!!!!! I didn't know about the following formula: ":Transmission per unit is equal to MVA_Base_3_Phase/Fault_Duty_3_Phase " but your approach makes perfectly sense to me. I would be curious to know how they derived this formula. Can you email, post or refer me to a book talking about...

A 1,000 KVA, 12.47KV- 480Y/277-V transformer with 4% impedance feeds a 480-V bus. The fault duty of the 12.47-KV system is 40MVA. Assuming the transformer and the 12.47KV system have the same X/R ratio, the 3-phase short circuit current(Amperes) avaliable at the 480-V bus is mostlynearly: I am...