No, that's the unit weight of a solid block of soil - with no voidsunit weight of soil = specific gravity * density of water = 2.66 * 62.4 = 165.98 lb/ ft^3
Is this for a Proctor Test?I agrree with civilized_nah. You need more information either S,e, or V.
Something is missing from your question, you have weight of soil = 3.2; what is the size of the sample?
agree ---that is the unit weight of solids in the soil composition.
@ civilized_naah, can't you calculate it this way?
so if you draw the mass-volume diagram
you can assume for 1 cu.ft of soil.
mass of soilds = 165.98 lb
given the water content of 12.8%, mass of water = mass of soilds * water content = 21.25 lb
mass of voids = 0
and so total mass = 165.98 + 21.25 = 187.23 lbs for 1 cu.ft. or in other words, wet unit weight of soil = 187.23 lb/ cft?
Thanks
Well if you are making the assuption Vv=Vw, or totally saturated, where S=1, you can use e=w(SG)/S = .128(2.66)/1 so e=0.3405:mail-296:
can somebody please comment on my answer below? Did I do it right?
Thank you!
agree ---that is the unit weight of solids in the soil composition.
@ civilized_naah, can't you calculate it this way?
so if you draw the mass-volume diagram
you can assume for 1 cu.ft of soil.
mass of soilds = 165.98 lb
given the water content of 12.8%, mass of water = mass of soilds * water content = 21.25 lb
mass of voids = 0
and so total mass = 165.98 + 21.25 = 187.23 lbs for 1 cu.ft. or in other words, wet unit weight of soil = 187.23 lb/ cft?
Thanks
Well if you are making the assuption Vv=Vw, or totally saturated, where S=1, you can use e=w(SG)/S = .128(2.66)/1 so e=0.3405:mail-296:
can somebody please comment on my answer below? Did I do it right?
Thank you!
agree ---that is the unit weight of solids in the soil composition.
@ civilized_naah, can't you calculate it this way?
so if you draw the mass-volume diagram
you can assume for 1 cu.ft of soil.
mass of soilds = 165.98 lb
given the water content of 12.8%, mass of water = mass of soilds * water content = 21.25 lb
mass of voids = 0
and so total mass = 165.98 + 21.25 = 187.23 lbs for 1 cu.ft. or in other words, wet unit weight of soil = 187.23 lb/ cft?
Thanks
Now you can get the dry unit wgt Yd = (SG)Yw/(1+e) Yd = (2.66)62.4/(1.3405) Yd = 123.82 pcf
Ysat = (1=w)Yd =139.7pcf
You might note the dry unit weight of sand is 100pcf, wet ~125 pcf, gravel dry 95, wet 125, wet clay 125 pcf. And solid basalt is about 188 pcf and solid granite ~168 pcf.
So when you consider that and get wet weight of 187 pcf and a dry weight of 167 pcf, you might have missed something.
I had to work a lot of these problems, because I did the same thing you did.
I hope this helps.
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