owillis28
Well-known member
Haven't done a flow net since college.
Total head loss (headwater to tail water) = 12
Number of equipotential drops= 0.80 foot/drop
Can anyone explain to me how the headwater to Point A = 9.5 FT? (12 * 0.80 = 9.6??)
Did they take 12 * 0.80 * 0.80 = 7.6 (7.68)
I am confused with the solution to this problem. My first answer was C but I knew it wasn't that easy.
I tried to solve this problem with the CERM using Equ. 21.36 but didn't even come close.
Total head loss (headwater to tail water) = 12
Number of equipotential drops= 0.80 foot/drop
Can anyone explain to me how the headwater to Point A = 9.5 FT? (12 * 0.80 = 9.6??)
Did they take 12 * 0.80 * 0.80 = 7.6 (7.68)
I am confused with the solution to this problem. My first answer was C but I knew it wasn't that easy.
I tried to solve this problem with the CERM using Equ. 21.36 but didn't even come close.
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