PPI Camara Practice Problem 98

[bripgilb]

Ladies and Gents,

Was working out this practice problem in PPI Camara.  Problem #98.

I got 100degrees.

Looking through the solution I see that they put: (cos(180))=0...  well I got: cos(180)=-1

Thoughts?  Please, see references.



AND GOOD LUCK TO ALL OF THOSE TAKING THE EXAM THIS FRIDAY!

Thanks,

Brip

 

[bobbilly]

I got the same thing as you but cos^-1(-0.4659) = 117 degrees.

https://www.wolframalpha.com/input/?i=.17+%3D+(1%2Fpi)+*+integral+from+X+to+pi+of+sin(theta) Answer is 2.055 radians which is 117 degrees

 

[jshar17]

Check the errata on ppi's site. It's updated for 120deg. This integral can be quickly done with TI 36x pro or equiv.

 

[bobbilly]

Since we are on the topic of rectifiers, if this was a half wave rectifier we would need to change 1/pi to 1/(2*pi)??

 

[helphere]

Since we are on the topic of rectifiers, if this was a half wave rectifier we would need to change 1/pi to 1/(2*pi)??

yes