Power Transfer Formula

[applepieordie]

Please explain to me why sin(delta2) = (P1/P2)*sin(delta1)

I don't understand how it got to that step. can someone please show the steps leading up to how sin(delta2) is determined? Thanks!

 

[Omer]

I think they got this one wrong also.

there is a direct relation between P and sin delta.  As P increase, so does the voltage angle and its sin.

in this case P increased by 10% so new sin delta2 is also 10% more than sin delta1.

therefore,  sin delta2= (1.1/1) sin delta.

 

[rg1]

I think they got this one wrong also.

there is a direct relation between P and sin delta.  As P increase, so does the voltage angle and its sin.

in this case P increased by 10% so new sin delta2 is also 10% more than sin delta1.

therefore,  sin delta2= (1.1/1) sin delta.

You are absolutely right @Omer . If E1, E2, X are same ; Delta will increase to get more P.  So Sine(Delta2)= 1.1*Sin25.5

 

[speedysc2]

@applepieordie what book is this question from?

 

[Stephen2awesome]

@applepieordie what book is this question from?

I second this.