i understand how we obtained overhaul distance. but then, how can you make that logic proportioning? i dont understand the logic here. with the same logic, in the attachment it said freehaul volume = overhaul volume.. why?Thanks JM.
Okay, this is how I did it (before looking at the answer).
The total distance the dirt needs to be hauled is from 9+63 to 15+21. 1521 - 963 = 558 total feet
The freehaul (the maximum distance in which the contractor is required to move the dirt before he can charge additional money) is 1456 - 1039 = 417 feet
So, the overhaul (the distance beyond the freehaul) must be 558' - 417' = 141 feet
If the overhaul distance of 141' results in 642,186 CY-ft, then what does the freehaul distance of 417' result in? Using ratio: 141/642,186 = 417 / x, x = 1,899,230.9 CY-ft
Divide by the freehaul footage and you get 1,899,230.9 CY-ft / 417 ft = 4554.5 CY
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