Hi Saad85,
This problem is an energy balance type. The energy gained by the hot water(Points 2 to 4) is transferred from the steam (Points 1 to 3).
Points 2 - 4 -> Energy (Btu/min) = 60,000 lbm/min * (375.12 Btu/lbm - 238.95 Btu/lbm) = 8,170,200 Btu/min
This value must equal the change in Btu/min from points 1 to 3. However, you need to first use the steam tables to find the enthalpy of point 3. At 110 psia, the saturated liquid enthalpy is 305.8 Btu/lbm
Points 1- 3 -> Energy (Btu/min) = 8,170,200 Btu/min = x lbm/min * (1231.3 Btu/lbm - 305.8 Btu/lbm)
Solve for X (lbm/min) -> x = 8,827 lbm/min
The closest answer is 8,800 lbm/min