That is what I get when I use the 1st equation you have there. I think that is how they should solve it going forward so they are following the Handbook.Vdc = 3 sqrt2 208/Pi =280.9
280.9 - 60 = 220.9/10 = 22.1 Ohm
22.1-2.5 = 19.6 Ohm
btw 0.955 x (sqrt2 x 208) = 280.9
0.955 = 3/Pi
I'm taking it the 21st. Hoping to be in the same boat as you very soon!Thanks for response, I passed the PE so thank the LAWD I don't have to deal with this anymore lol
YOU GOT THIS YOU GOT THIS! Hard work! I had over 500 hours studied and 2,500 hundred problems worked so I came in very prepared for it lol!That is what I get when I use the 1st equation you have there. I think that is how they should solve it going forward so they are following the Handbook.
I'm taking it the 21st. Hoping to be in the same boat as you very soon!
Thanks! I started preparing last November for it in preparation for the April 2020 exam and now here we are. Since I have you here, I have the following practice exams:YOU GOT THIS YOU GOT THIS! Hard work! I had over 500 hours studied and 2,500 hundred problems worked so I came in very prepared for it lol!
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