Has anybody else worked #513 without using per-unit analysis?
I've searched the forum for examples without any luck. The per-unit solution in the NCEES book does not help me at all.
I worked it without the PU conversion and came up with an answer of 418A (the answer given is 415A). My solution took a total of 2 lines and seemed much simpler than the PU analysis.
Because the transformer impedance is based on the percentage of voltage drop internal to the transformer I have:
V= 92.5% (or 100%-7.5%) of 12kV = 11.1kV
I=(V/sqrt3)/R where V=11.1kV and R=15.312ohms
Anything wrong with my assumptions? Did I get the right answer by dumb luck?
I've searched the forum for examples without any luck. The per-unit solution in the NCEES book does not help me at all.
I worked it without the PU conversion and came up with an answer of 418A (the answer given is 415A). My solution took a total of 2 lines and seemed much simpler than the PU analysis.
Because the transformer impedance is based on the percentage of voltage drop internal to the transformer I have:
V= 92.5% (or 100%-7.5%) of 12kV = 11.1kV
I=(V/sqrt3)/R where V=11.1kV and R=15.312ohms
Anything wrong with my assumptions? Did I get the right answer by dumb luck?