nuclear bus
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I just can't get this one to work out and I hope somebody here can help.
3-phase 460 V, 25 hp induction motor, 34 A, 0.75 lagging p.f.
I understand that the Smotor = 28.3 angle 41.4 degrees KVA. Based on that the following should be true.
Pmotor = 21.23
Qmotor = 18.72
because P = S cos (angle), and Q = S sin (angle) where the angle = 41.1 degrees.
So...if we want to improve the p.f. to 0.90 lagging, then the new S would be still 28.3 but at an angle 25.84 degrees KVA right?
thus the new Pmotor = 25.47 and new Qmotor = 12.33 right?
The solution shows the new Qmotor = 10.3, and that obviously throws everything off. Not sure where they get the "21.7" value for "P" in the solution either.
This seems like it should be pretty straightforward but I just don't get it. Does anybody have any clues they can offer? Thanks in advance for your help.
3-phase 460 V, 25 hp induction motor, 34 A, 0.75 lagging p.f.
I understand that the Smotor = 28.3 angle 41.4 degrees KVA. Based on that the following should be true.
Pmotor = 21.23
Qmotor = 18.72
because P = S cos (angle), and Q = S sin (angle) where the angle = 41.1 degrees.
So...if we want to improve the p.f. to 0.90 lagging, then the new S would be still 28.3 but at an angle 25.84 degrees KVA right?
thus the new Pmotor = 25.47 and new Qmotor = 12.33 right?
The solution shows the new Qmotor = 10.3, and that obviously throws everything off. Not sure where they get the "21.7" value for "P" in the solution either.
This seems like it should be pretty straightforward but I just don't get it. Does anybody have any clues they can offer? Thanks in advance for your help.