The amplitude of the current is given as a peak value. For AC power, RMS values are used.
Irms = Ipeak / sqrt2
Yes. If the signals have the same frequency and are in phase, then you can add the amplitudes.Okay so if the frequencies of the two components were the same then the equation:
(7/SQRT2)^2 * 3 would be true?
However Since the frequencies are different we must use the equation:
3*(5/SQRT2)^2 + 3*(2/SQRT2)^2
Maybe I was unclear.^I'm not so sure. The problem I have is that if either method can be used, then:
(7/SQRT2)^2 * 3 is equall to 3*(5/SQRT2)^2 + 3*(2/SQRT2)^2?
49*3/2 = 25*3/2 + 4*3/2
73.5 = 43.5
This one puzzles me as my first response is the same as benbo's.
I think we agree also. I'm coming down with a head cold and I think it's making my thinking a little muddled.I think we agree.
I'm going out of town for a couple days (although I may have internet access). So you won't have to beat me to it! Just Jim and any other EEs who get in on the fun. Besides, somebody is bound to ask something about power and leave me for dead.I concur.(really I'm just disappointed I didn't get to answer any questions. Darn job.)
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