Slay the P.E.
Well-known member
But you should get 0.179 — there has to be an error somewhere.My answer was also B but the calculated value I got was 0.23...answered in 6:23 min....
But you should get 0.179 — there has to be an error somewhere.My answer was also B but the calculated value I got was 0.23...answered in 6:23 min....
Maybe the calculatorBut you should get 0.179 — there has to be an error somewhere.
Yes.. instead of 49.05N for the friction force I wrote 45.05 when I took the natural log...that did it... I do get 0.179...whew....gotta watch out for these simple mistakes on the exam...thanks !But you should get 0.179 — there has to be an error somewhere.
Deflections at the ends are not zero, because the supports are compression springs which will be shortened upon the application of the load.Is this question set up right? Deflections at the ends will be zero. Maybe I'm missing something?
Please do you guys mind sharing your calculation? Thanks.A is the correct answer for the beam deflection problem. Use the principle of superposition to add the displacement of the load application point assuming rigid supports with an elastic beam plus the displacement of the load application point assuming a rigid beam but elastic supports.
Thank you so much. i got halfway and got stuck.
You beat me to it. Good work!
As a thermal-fluids guy, this makes my stomach hurt. :rotflmao:
Deflection? Easy! Now, enthalpy and entropy? WTH is that all about?!?!?!? Adiabati-wha????As a thermal-fluids guy, this makes my stomach hurt. :rotflmao:
I'll probably still look at these just for kicks... :bananalama:Is anyone else excited for practice problems of the week to start again? lol
My thoughts exactly. lol. To each their own..Deflection? Easy! Now, enthalpy and entropy? WTH is that all about?!?!?!? Adiabati-wha????
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