I solved it by process of elimination....I admit, it is not the most elegant way of solving, but it led me to C.
Yes. Choice "A" is actually a trap I created: If you solve the problem using the manometer equation (hydrostatics) you get the distance between the water surface and the tube's submerged end as roughly (2.75 psi)*(2.31 ftH2O/psi) = 6.3525 ft. Then you would get the volume as (80+6.3525ft)*(pi/4)*(4ft)^2 = 1085 ft^3. If you had overlooked the fact that they want the answer in gallons, you would choose (A).I solved it by process of elimination....I admit, it is not the most elegant way of solving, but it led me to C.
First, quick look at the problem, the answer A seem to have a suspiciously low value. Also answer D is sketchy.
So, the only possible good answers left are B and C.
Ballpark check, order-of-magnitude, and unit consistency/dimensional homogeneity are fantastic tools.Next, I calculated the volume of the entire well:
100ft*(pi/4)*(4ft)^2*(7.48 gal/1ft^3)=9,400 gal. Which emphases again that the answers is lying between B and C. Ballpark check!
I love it.Time : under 5 minutes.
It's my subjective judgment. I considered the hardest problem I've seen in the exam as a 5 and the easiest a 1. Don't worry about this. This difficulty level is irrelevant and now I'm regretting having put that there.When you say difficulty 2, are you grading it based on actual exam difficulty or just based on how your own perspective?
OkIt's my subjective judgment. I considered the hardest problem I've seen in the exam as a 5 and the easiest a 1. Don't worry about this. This difficulty level is irrelevant and now I'm regretting having put that there.
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