4 leg Intersection in an urban area, speed is 45 MPH, width of each leg is 48'. Average length of vehicle is 20', deceleration is 11.2ft/sec. Piev is 2.0 seconds
clearance time is included in yellow interval.
What is most nealry the min yellow time
A.2.5 secs
B. 4.0
C. 5.5
D 6.0
I got the answer correct, however the solution uses an odd formula. I looked at the clearnce time, then calculated the time needed to stop from a speed of 45MPH using deceleration of 11.2. Lindberg adds the PIEV time to the clearance time then adds that to the deceleration time but doubles the deceleration rate. t= v/2a
I approached this as the min yellow time would be the longer of the times when comparing the time needed to slow down versus the time needed to clear the intersection.
Where is the t=v/2a coming from and is my approach valid?
Thanks
clearance time is included in yellow interval.
What is most nealry the min yellow time
A.2.5 secs
B. 4.0
C. 5.5
D 6.0
I got the answer correct, however the solution uses an odd formula. I looked at the clearnce time, then calculated the time needed to stop from a speed of 45MPH using deceleration of 11.2. Lindberg adds the PIEV time to the clearance time then adds that to the deceleration time but doubles the deceleration rate. t= v/2a
I approached this as the min yellow time would be the longer of the times when comparing the time needed to slow down versus the time needed to clear the intersection.
Where is the t=v/2a coming from and is my approach valid?
Thanks