In the Kaplan sample afternoon exam problem #38 I understand the solution they give however I'm curios if thres another way to find thid solution.
They used the Iab current dropped across the 10ohm resistor to determine the voltage dropped across the resistor and then use this voltage drop subtracted from Vac to find the Vcn voltage.
Can you find the same solution by calculating the voltage drop across the -j10ohm capacitor and then subtract this voltage to find Vcn? To do this would you have to use Iba current phasor instead of Iab? Also would you use Vbc or Vcb to subtract the voltage across -j10 capactor from?
I'll try to scan and post the problem tomorrow.
They used the Iab current dropped across the 10ohm resistor to determine the voltage dropped across the resistor and then use this voltage drop subtracted from Vac to find the Vcn voltage.
Can you find the same solution by calculating the voltage drop across the -j10ohm capacitor and then subtract this voltage to find Vcn? To do this would you have to use Iba current phasor instead of Iab? Also would you use Vbc or Vcb to subtract the voltage across -j10 capactor from?
I'll try to scan and post the problem tomorrow.