I'm currently working on a problem shown below. Bear with me, I need to go through my calculation first before I can ask my question...
"A generator provides 400 VAC at 500 Hz turning at 14,000 rpm under full load. Calculate (a) How many poles does it have? (b ) What is the speed regulation, SR(%)?"
Here's how I solved the problem:
(a) How many poles does it have?
sync rpm = 120 * f / p
Since sync rpm is not provided, I used the full-load rpm and solved for 'p' . Once solved, I rounded it down to the nearest multiple of 2.
14,000 = 120 * 500 / p
therefore, p = 4.28 = 4 (rounded down, since the number of pole is always a multiple of 2)
(b ) What is the speed regulation, SR(%)?
First, I calculate the sync rpm using the 'p' calculated in (a).
sync rpm = 120 * f / p
sync rpm = 120 * 500 / 4
sync rpm = 15000 rpm
Now, to solve the SR, I used the equation:
SR = (no-load rpm - full-load rpm) / full-load rpm
... now here's my question... since we were not given the no-load rpm in this problem, is it safe to assume that the sync rpm can be used instead? In other words, here's how I solved the SR
SR = (sync rpm - full-load rpm) / full-load rpm
SR = (15000 - 14000) / 14000
SR = 0.0714 = 7.1%
Is my SR answer correct? Or is it wrong because I used the sync rpm, not the no-load rpm, to calculate for SR. I understand that sync rpm is theoretically different from no-load rpm. But I'm not sure how to come up with the no-load rpm when it is not given in the problem.
Thank you. I appreciate any feedback you have for me.
yuyii
"A generator provides 400 VAC at 500 Hz turning at 14,000 rpm under full load. Calculate (a) How many poles does it have? (b ) What is the speed regulation, SR(%)?"
Here's how I solved the problem:
(a) How many poles does it have?
sync rpm = 120 * f / p
Since sync rpm is not provided, I used the full-load rpm and solved for 'p' . Once solved, I rounded it down to the nearest multiple of 2.
14,000 = 120 * 500 / p
therefore, p = 4.28 = 4 (rounded down, since the number of pole is always a multiple of 2)
(b ) What is the speed regulation, SR(%)?
First, I calculate the sync rpm using the 'p' calculated in (a).
sync rpm = 120 * f / p
sync rpm = 120 * 500 / 4
sync rpm = 15000 rpm
Now, to solve the SR, I used the equation:
SR = (no-load rpm - full-load rpm) / full-load rpm
... now here's my question... since we were not given the no-load rpm in this problem, is it safe to assume that the sync rpm can be used instead? In other words, here's how I solved the SR
SR = (sync rpm - full-load rpm) / full-load rpm
SR = (15000 - 14000) / 14000
SR = 0.0714 = 7.1%
Is my SR answer correct? Or is it wrong because I used the sync rpm, not the no-load rpm, to calculate for SR. I understand that sync rpm is theoretically different from no-load rpm. But I'm not sure how to come up with the no-load rpm when it is not given in the problem.
Thank you. I appreciate any feedback you have for me.
yuyii