ktulu
Well-known member
I am reworking through the morning problems from the NCEES Sample Exam.
The question I have pertains to masonry walls. The question asks for the total axial load, P, at the midheight of a 12 foot high wall.
Given:
Roof dead load = 15 psf
Non-reducible roof snow load = 40 psf
Average wall dead load = 54 psf
Design wind (pressure or suction) = 20 psf
Seismic forces do not govern...
Unfortunately, I have looked at the answer, and am confused as to where the constants come from. Specifically, the solution has:
P = 6*(average wall dead load) + 12*(roof dead load + non-reducible roof snow load) = 980 pounds per linear foot.
So, as I was writing this, I figured out that the 6 & 12 are wall heights, but now, how did they come up with the combination?
I know, it sounds like jumble, but I am confused as to how they solved this question....
ktulu
The question I have pertains to masonry walls. The question asks for the total axial load, P, at the midheight of a 12 foot high wall.
Given:
Roof dead load = 15 psf
Non-reducible roof snow load = 40 psf
Average wall dead load = 54 psf
Design wind (pressure or suction) = 20 psf
Seismic forces do not govern...
Unfortunately, I have looked at the answer, and am confused as to where the constants come from. Specifically, the solution has:
P = 6*(average wall dead load) + 12*(roof dead load + non-reducible roof snow load) = 980 pounds per linear foot.
So, as I was writing this, I figured out that the 6 & 12 are wall heights, but now, how did they come up with the combination?
I know, it sounds like jumble, but I am confused as to how they solved this question....
ktulu