Footing sizing question

[MaryJ]

If in my calculations I come up with the following answers"

Ultimate Bearing Capacity= 9877 psf

Net Bearing Capacity = 9523psf

Maximum applied pressure = 5079psf

(psf= pounds per squafe feet)

If the problem ask "Is the footing sized correctly". I know my answer should be no, but I don't know how to explain.

Is it because the net bearing capacity is more than the maximum applied load.

Thanks a million..

 

[outatime2002]

If in my calculations I come up with the following answers"
Ultimate Bearing Capacity= 9877 psf

Net Bearing Capacity = 9523psf

Maximum applied pressure = 5079psf

(psf= pounds per squafe feet)

If the problem ask "Is the footing sized correctly". I know my answer should be no, but I don't know how to explain.

Is it because the net bearing capacity is more than the maximum applied load.

Thanks a million..

If the capacity of the footing is greater than the demand, the footing is adequate as is. Why do you maintain that the footing is inadequate?

 

[outatime2002]

If in my calculations I come up with the following answers"
Ultimate Bearing Capacity= 9877 psf

Net Bearing Capacity = 9523psf

Maximum applied pressure = 5079psf

(psf= pounds per squafe feet)

If the problem ask "Is the footing sized correctly". I know my answer should be no, but I don't know how to explain.

Is it because the net bearing capacity is more than the maximum applied load.

Thanks a million..

If the capacity of the footing is greater than the demand, the footing is adequate as is. Why do you maintain that the footing is inadequate?

 

[Badger]

If in my calculations I come up with the following answers"
Ultimate Bearing Capacity= 9877 psf

Net Bearing Capacity = 9523psf

Maximum applied pressure = 5079psf

(psf= pounds per squafe feet)

If the problem ask "Is the footing sized correctly". I know my answer should be no, but I don't know how to explain.

Is it because the net bearing capacity is more than the maximum applied load.

Thanks a million..

If you are using the CERM:

q(net) = q(ult) - (gamma)Df

q(allowable) = q(net)/FS

So in your case your factor of safety FS = 9523/5079 = 1.875

If your FS = 2, the footing is sized wrong, if FS = 1.8 is acceptable then the footing is okay.

I hope this helps.