Hi guys,
Regarding preventing overcurrent damage to a diode, I understand the reasoning behind using a 2nd diode in parallel (to divide the current).
But is there a reason why adding resistors to the diode branch is not an appropriate solution to reducing current? Is because of resistor I^2 * R losses? The solution in Shorebrook PE Power Exam Question 46 does not elaborate on this.
Thanks!
Regarding preventing overcurrent damage to a diode, I understand the reasoning behind using a 2nd diode in parallel (to divide the current).
But is there a reason why adding resistors to the diode branch is not an appropriate solution to reducing current? Is because of resistor I^2 * R losses? The solution in Shorebrook PE Power Exam Question 46 does not elaborate on this.
Thanks!