Greetings,
I'm trying to confirm my train of thought is correct for a problem that I've come across. The problem is:
MethylMercaptan (CH3SH) is produced from stoichiometric amounts of H2S and methanol (CH3OH) by reaction:
CH3OH + H2S -> CH3SH + H2O
Molecular Weights:
CH3OH 32.0
H2S 34.1
CH3SH 48.1
H2O 18
The H2S selectivity (percentage of the total conversion to the desired product) is 90%. The other products are formed from the reaction of methanol and H2S. Of the feed to the reactor (fresh feed pluc recycle), 85% reacts on each pass through the reactor. The unreacted feed containing stoichiometric amounts of H2S and methanol is recycled.
The fresh feed (lb mol/hr) of H2S required to produce 1,000 lb/hr of mercaptan is most nearly.
A. 19
B. 21
C. 23
D. 27
My approach:
Lb mols/hr of CH3SH out of seperator
1,000 lb/hr ( 1 lb mol/48.1 lbs) = 20.79 lb mols/hr CH3SH
The way I read it, based on the amount entered into the reactor, 85% actually reacts and 90% of that is converted. So
Lb mols/hr of H2S
20.79 lb mols/hr (1/0.85)(1/0.9) = 27.17 lb mols/hr H2S
The book does not take into account the 85% reacting, so their answer is 20.79/0.9 = 23.1. My question is, is my logic sounds and I should ignore the book?
Thanks a bunch for the help!
I'm trying to confirm my train of thought is correct for a problem that I've come across. The problem is:
MethylMercaptan (CH3SH) is produced from stoichiometric amounts of H2S and methanol (CH3OH) by reaction:
CH3OH + H2S -> CH3SH + H2O
Molecular Weights:
CH3OH 32.0
H2S 34.1
CH3SH 48.1
H2O 18
The H2S selectivity (percentage of the total conversion to the desired product) is 90%. The other products are formed from the reaction of methanol and H2S. Of the feed to the reactor (fresh feed pluc recycle), 85% reacts on each pass through the reactor. The unreacted feed containing stoichiometric amounts of H2S and methanol is recycled.
The fresh feed (lb mol/hr) of H2S required to produce 1,000 lb/hr of mercaptan is most nearly.
A. 19
B. 21
C. 23
D. 27
My approach:
Lb mols/hr of CH3SH out of seperator
1,000 lb/hr ( 1 lb mol/48.1 lbs) = 20.79 lb mols/hr CH3SH
The way I read it, based on the amount entered into the reactor, 85% actually reacts and 90% of that is converted. So
Lb mols/hr of H2S
20.79 lb mols/hr (1/0.85)(1/0.9) = 27.17 lb mols/hr H2S
The book does not take into account the 85% reacting, so their answer is 20.79/0.9 = 23.1. My question is, is my logic sounds and I should ignore the book?
Thanks a bunch for the help!