Camara Sample Exam - Morning #16

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NVRSTOP

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16. A voltage of v(t) = (339.5V)sin2512t is applied to a 30 microF capacitor that was initially uncharged. (t is measured in seconds.) What is the approximate current in the capacitor at 0.625s?

Solution indicates:

i(t) = C * dv(t)/dt

= C (d((339.5V)sin 2512t)/dt)

= C (339.5V)(d(sin 2512t)/dt)

= C (339.5V)((2512s^-1)cos 2512t)

= (30 x 10^-6 F)(339.5 V)(2512 s^-1) x cos((2512s^-1)(0.625 x 10^-3 s))

= 0.020 A

I am getting 1.17 (I'm converting 2512 to degrees (mult by (180/pi) = 143,927.

I'm sure it's a conversion that I am missing here, I just do not see it right now.

NVRSTOP

 
I'm away from my calculator right now so I'm struggling a little bit with the math.

Are you converting 2512 radians to degrees or are you converting 2512*0.625*10-3?

If you don't get a better answer, I'll take another shot at it when I get home.

Jim

 
I'm away from my calculator right now so I'm struggling a little bit with the math.
Are you converting 2512 radians to degrees or are you converting 2512*0.625*10-3?

If you don't get a better answer, I'll take another shot at it when I get home.

Jim

Converting 2512 radians to degrees - 2512(180/pi) = 143,927

Thanks

 
16. A voltage of v(t) = (339.5V)sin2512t is applied to a 30 microF capacitor that was initially uncharged. (t is measured in seconds.) What is the approximate current in the capacitor at 0.625s?
Solution indicates:

i(t) = C * dv(t)/dt

= C (d((339.5V)sin 2512t)/dt)

= C (339.5V)(d(sin 2512t)/dt)

= C (339.5V)((2512s^-1)cos 2512t)

= (30 x 10^-6 F)(339.5 V)(2512 s^-1) x cos((2512s^-1)(0.625 x 10^-3 s))

= 0.020 A

I am getting 1.17 (I'm converting 2512 to degrees (mult by (180/pi) = 143,927.

I'm sure it's a conversion that I am missing here, I just do not see it right now.

NVRSTOP
You need to convert the entire expression "(2512s-1)(0.625*10^10-3)" to degrees.

2512*0.625*10-3=1.57radians

1.57radians*180/pi= 89.95 deg.

I'm teaching myself how to do trig functions on excel while doing this so double-check the math.

Jim

 
Last edited by a moderator:
You need to convert the entire expression "(2512s-1)(0.625*10^10-3)" to degrees.
2512*0.625*10-3=1.57radians

1.57radians*180/pi= 89.95 deg.

I'm teaching myself how to do trig functions on excel while doing this so double-check the math.

Jim

Nice work!

I worked it this way, but I converted the 2512 in front of the cos function to degrees and it gave me an answer of 1.27 A. Not thinking as clearly as usual. A little sleep deprived this weekend. Been hitting the books pretty hard the past two(2) weeks.

Thanks again Jim

 
Could someone point me to the correct spot in the EERM or the practice problems to review a few poblems like this...I can't seem to find them?

Thanks,

Jason

 

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