16. A voltage of v(t) = (339.5V)sin2512t is applied to a 30 microF capacitor that was initially uncharged. (t is measured in seconds.) What is the approximate current in the capacitor at 0.625s?
Solution indicates:
i(t) = C * dv(t)/dt
= C (d((339.5V)sin 2512t)/dt)
= C (339.5V)(d(sin 2512t)/dt)
= C (339.5V)((2512s^-1)cos 2512t)
= (30 x 10^-6 F)(339.5 V)(2512 s^-1) x cos((2512s^-1)(0.625 x 10^-3 s))
= 0.020 A
I am getting 1.17 (I'm converting 2512 to degrees (mult by (180/pi) = 143,927.
I'm sure it's a conversion that I am missing here, I just do not see it right now.
NVRSTOP
Solution indicates:
i(t) = C * dv(t)/dt
= C (d((339.5V)sin 2512t)/dt)
= C (339.5V)(d(sin 2512t)/dt)
= C (339.5V)((2512s^-1)cos 2512t)
= (30 x 10^-6 F)(339.5 V)(2512 s^-1) x cos((2512s^-1)(0.625 x 10^-3 s))
= 0.020 A
I am getting 1.17 (I'm converting 2512 to degrees (mult by (180/pi) = 143,927.
I'm sure it's a conversion that I am missing here, I just do not see it right now.
NVRSTOP