3-phase induction motor: change in slip inversely related to square of change in voltage? (Eng. Pro Guides Full Exam Question 23)

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akyip

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Hi guys,

Re-doing the Engineering Pro Guides Full Exam, there's one concept I don't quite understand about induction motors from this exam

On Problem 23's solution, it briefly mentions that if induction motor slip is significant, then change in slip is related to square of change in voltage through this formula:

(new slip / old slip) = (old voltage / new voltage)^2

new slip = old slip * (old voltage / new voltage)^2

I tried to find out more about this through the Engineering Pro Guises textbook and the Wildi textbook, but could not find anything that explains this formula inversely relating change in slip to square of change in voltage... can anyone provide an explanation for this? I'm hoping to understand this better so that I don't have to memorize this...

Thanks!

 
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