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Also used 4:30 to 5:30 = C

V=2728

Also for equal radius curves p =parallel offset p=2r(1-cos∆) ∆=acos[1-(p/2r)] r=1/2p/(1-cos∆) D=2r*sin∆

My first answer was wrong. I used 440 instead 1/2.  Atan a/b = Atan 60/220 = 15.2551 this 1/2 delta Delta = 2 x 15.2551 R= y/(1-cos delta) = 60/(1-cos 30.5102)=433.33

R=1643.34

In my notes these are some equations used for steps for calculating Signal Timing...  L= total  lost time in all phases ;  l = total lost time in each phase; C = optimum cycle length; g = effective green time to each phase based on its critical v/s; G = Green interval; Y = yellow; R = Red...

D-E    S 47^ 23' 27" E    1033.985 Links E-F    38.997 Links Area is 46739.125 SQ/Ft       1.073 Acres Used CADD

Self-studying and using a online PE review course thru ITRE. I have the CERM's, review course books (they cover all civil topics) and all the transportation reference material except one of the pavement books. My downfall is my education HS only. Been doing surveying and highway design for over...

Here is my results from April 2016 need some work on a few topics.  I walked out kicking my self on 3 questions in the afternoon knowing i had answered them wrong. Any advise besides the Obvious STUDY STUDY and STUDY more.

Civil Transportation 50/80 ---- 25 morning, 25 afternoon

I'm guessing Dec 11th for the early states, but could be anywhere between 4th - 18th. Using historic data in days form the last few years.

The "depth" of problems on the am portion. I guess I should of said "type" but more detail

I was not satisfied with my performances on the am or its depth. Now the pm was great, I was prepared and quessing I got 33+. I am right on the break point of 56 needed. May be taken again in April.

Civil Transportation also.... Morning was a nightmare but I shook it off and the afternoon was a breath of fresh air. Am 20-23 pm 30-33 plus the hell Mary answer on the remaining. Will be studying for April.

Also see pages 23-13 - 23-15 HCM Example is on 23-28 Can't edit post

HCM example problem for equations 22-28 F=(Fp+0.5Fm) Fp=Qsb/PHF(1-Sp/Sb) FM=Qob/PHF(1+Sp/Sb) Qsb=90 b/h Qob=90 b/h PHF=.90 Sp=3.5 Sb=12Mph*1.47=17.64 You are correct it is 140.149 I had not covered mph/ft/s See exhibit 23-4 HCM page 23-4

F=135.416 LOS D C)

Yes it meets. HW=8.25 No HW=16.25 @ 500cfs overtop by 2.25ft

Sorry about the double post... Trying to get the adding quote. The column are for case 1-3 and the design traffic conditions are A-C within each case. Also believe C to be correct.