Their corrections of the solutions are still full of massive errors. It's ridiculous. Their solution looks a mess at this point.
Qtn:
3phase 11MVA Gen (Xd"=0.39j pu) serves 6MVA 5/25kV transformer (6% impedance). What is The MVA contribution at the generator with a fault at the transformer...
Doesnt say how the generator or the transformer is connected.
But for per unit i dont think the sqrt(3) comes into it. think that is one of the points of per unit.
I think the dividing by 25kV is correct. (not 25kVA)
I think you are right.
The z conversion is Zold x (Snew/Sold) x (Vold/Vnew)^2
which is what you have - specifically for the kVA being 6/11
They have 11/6 which is (Sold/Snew) - switching from 11MVA to 6MVA and from 5kV to 25kV
They say 11MVA to be converted to 6MVA but have calculated it the...
last week. seems you must have older versions.
I think Josh mentioned this in another post, so your references to questions wouldnt apply to most people.
Josh,
I appreciate the detailed reply. thanks. Didnt mean it as any attack or to be taken so personally.
I was just trying to get my study and everything sorted early - not last minute preparation in September and October. But it seems that others seem to feel this is the time they really get...