Recent content by Phalanx

I suggest reading the notes for Figure 28.6-1 to gain a better understanding of wind design. In particular, note 2 specifies that both load cases need to be assessed for every corner (i.e. 8 total load cases) and refers the reader to Figure 28.4-1. The pressure for each zone (A, B, C, etc)...

Unistrut has a pretty slick way to stiffen threaded rods. Essentially, a piece of strut is bolted to the threaded rod using a cradle clip assembly. With the cradle clips installed, the system is usually controlled by buckling of the strut. If the steel pipe is used as a compression member, it...

I work in Hillsboro.

McEngr, Shear lag is an effect, not a strength. It is similar to a Whitmore section when designing gusset plates. The Whitmore section is part of the tension yielding strength of a gusset, but it is not considered the Whitmore yielding strength. The net section is influenced by the type of...

1) A PE is a registered Professional Engineer. There are a few basic steps to becoming one: A) Obtain an ABET accredited degree. Some states accept an Engineering Technology degree, but many require a bachelor's degree. B) Take the Fundamentals of Engineering exam (aka FE or EIT exam)...

I went two years without a raise before moving on to bigger and better things. This year, my department received a small COLA.

I don't have either of those books, but here is my take on the issue. If the column has only axial load, then the phi factor is 0.65 (compression failure). If the base of the column is fixed, phi will vary from 0.65 to 0.9 depending on whether the section is tension/compression controlled. In...

The value of At/s used in equation 11-24 is the greater of 25bw/fy and Tu/(2*.85*Aoh/fy) (Eq 11-21). Do not use (Av + 2At)/s because the AL requirements are independent of shear.

According to the NCEES outline for the Civil-Structural exam, timber design will be based on ASD. There is no mention of ASD vs. LRFD for timber design on the outlines for the Structural I or II exams. ASD will mostly likely be the method of choice. Masonry is a little different. Straight...

I am not a transportation expert by any means, but I'll take a stab at this problem. To check the MAXIMUM curve length, use the following: x = 0.5*L + 120 ft ELEVx = 167.65 + 3 = 170.65 ft ELEVbvc = 167.65 + .012*(L/2) = 167.65 + .006*L R = (.008 + .012)/L = .02/L Using equation 78.47 in...

I didn't see "steel design" listed on the NCEES outline for the construction exam, but I may have missed it. Although "steel design" is listed as a subject on the morning exam, I don't think any questions will require using the steel manual. My reasoning: If the steel manual is needed for the...

I agree with ngnrd. Contact your state's board since their opinion is the only one that counts. I will tell you that in Oregon, you can gain experience for an internship only if you work for 6 months and do not attend school full time. With those rules, the only experience that counts for you...

You need to know the overall change in temperature to figure out the change in length. T1 = final temp T2 = initial temp Total temp change = T1 - T2 => 40 - (-10) = 40 + 10 = 50 degrees. Think of it this way: The beam was heated up 10 degrees just to get it back to 0, and now it's being...

My goal was to do at least one problem every day, but I never forced myself to study for a specific length of time. I figured that as long as I was willing to continue then I was being productive. If I started to lose focus or get too distracted, I quit studying. Usually I was finished after...

You are correct and so is the solution. The formula for future worth is: F = P*(1+i)^n This equation is on pg. 86-7 in the CERM 11th ed. In this case, you will have to calc the number by hand since the CERM does not have a table for 2.5%.