Can someone please explain why 12.5KV is divided by under-root 3 in NCEES solution?
This is how I solved this problem;
Vab=12.5 angle 0 + voltage drop across single phase line
= 12.5 angle 0 + 70 angle -20 * (5+j10)
= 13.08 KV angle 2.35
Since the load is Delta, phase voltage would be equal to line voltage.
Am I missing something?
This is how I solved this problem;
Vab=12.5 angle 0 + voltage drop across single phase line
= 12.5 angle 0 + 70 angle -20 * (5+j10)
= 13.08 KV angle 2.35
Since the load is Delta, phase voltage would be equal to line voltage.
Am I missing something?