LMAO
Well-known member
I bumped into another problem; an AC motor which is normally Delta connected draws 367A starting current; what would be the starting current if it is started in Wye configuration?
I thought the answer should be 367x3=1101, because Wye impedance is one third of delta impedance. But the answer in the book has it other way around; it shows to be 367/3=122.3.
Any thought?
I thought the answer should be 367x3=1101, because Wye impedance is one third of delta impedance. But the answer in the book has it other way around; it shows to be 367/3=122.3.
Any thought?